(x+1)/(x^2-7x+12)=0

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Solution for (x+1)/(x^2-7x+12)=0 equation: 


D( x )

x^2-(7*x)+12 = 0

x^2-(7*x)+12 = 0

x^2-(7*x)+12 = 0

x^2-7*x+12 = 0

x^2-7*x+12 = 0

DELTA = (-7)^2-(1*4*12)

DELTA = 1

DELTA > 0

x = (1^(1/2)+7)/(1*2) or x = (7-1^(1/2))/(1*2)

x = 4 or x = 3

x in (-oo:3) U (3:4) U (4:+oo)

(x+1)/(x^2-(7*x)+12) = 0

(x+1)/(x^2-7*x+12) = 0

x^2-7*x+12 = 0

x^2-7*x+12 = 0

DELTA = (-7)^2-(1*4*12)

DELTA = 1

DELTA > 0

x = (1^(1/2)+7)/(1*2) or x = (7-1^(1/2))/(1*2)

x = 4 or x = 3

(x-3)*(x-4) = 0

(x+1)/((x-3)*(x-4)) = 0

x+1 = 0 // - 1

x = -1

x = -1

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